Question

A straight elastic string has one end fixed at A(2,5) and the other end is at B(1, 0). AB is
stretched to C along the line AB such that AC = 3 AB. Find the coordinates of C.

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Answer 1

Answer:

Given

AC=3AB

so that C is dividing the line extrnally

AB:AC=1:3

let (x,y)be the point C

now

C(x,y)=[(mx2-nx1)÷m-n,(my2-ny1)÷m-n]

=[3(1)-1(2)÷3-1,3(0)-1(5)÷3-1]

=[3-2÷2,-5÷2]

=[1/2,-5/2]

so(1/2,-5/2) is the point C

Answer 2

Answer:

5/2,15/2

Step-by-step explanation:

use external section formula

mx2-nx1/m-n