Question

A straight highway leads to the footof the tower ,a man standing at the top of the tower,observes a car at an angle of depression of 30° which is approaching the foot of the tower with uniform speed.6 seconds later ,the angle of depression of the car is found to be 60°. Find the time taken by car to reach the foot of the tower from this point

Answer 1

Good Morning

Here is your solution:

Let the distance traveled by the car in 6seconds=AB=X metres

Height of the tower CD=h metres

The remaining distance to be traveled by the car BC =d metres

AC =AB+BC=x+d metres

ANGLE PDA=ANGLE DAC=30

ANGLE PDB=ANGLE DB*C=60

TRIANGLE BCD TAN60=CD/BC=root3=h/d

h=root3d

TRIANGLE ACD TAN30=CD/AC

1/root3=h/(x+d)

h=(x+d)/root3

(x+d)/root3=root3d

x+d=3d

x=2d

d=x/2

Time taken to travel x metres =6seconds

Time taken to travel the distance of D metres i. e., x/2=6/2=3seconds

Answer 2

Answer:

Step-by-step explanation: