Question

find the sum of all the first n even natural numbers​

Answer 1

Answer:

110 answer

hope its help you

Answer 2

Answer:

$\huge\boxed{\boxed{Hope\:it\:helps\:you}}$

The sum of the first n even natural numbers is n [n + 1].

Given :  

First n even natural numbers are 2,4 ,6 ,………., 2n  which forms an AP.

Here, a = 2, d = 4 - 2 = 2

By using the formula ,Sum of nth terms , Sn = n/2 [2a + (n – 1) d]

Sn = n/2 [2(2) + (n -1) 2]

Sn = n/2  [4  + 2n – 2]

Sn = n/2 × 2 [2  + n – 1]

Sn = n [n + 1]

Hence, the sum of the first n even natural numbers is n [n + 1].