a straight line AB is bisected at C and produced to D.show that
AB+BD=2CD
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HO FRIEND...
SO......AC = CB
AC=CB
AD=AB+BD
AD+BD=AB+2BD
AD+BD=AC+BD+CB+BD
AD+BD=CB+BD+CB+BD
so.... (AC=CB)
AD+BD=CD+CD
AB+BD= 2CD....
HOPE THIS HELPS U.....
SO......AC = CB
AC=CB
AD=AB+BD
AD+BD=AB+2BD
AD+BD=AC+BD+CB+BD
AD+BD=CB+BD+CB+BD
so.... (AC=CB)
AD+BD=CD+CD
AB+BD= 2CD....
HOPE THIS HELPS U.....
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