Question

A straight line is drawn joining the points (3, 4) and (5, 6). If the line is extended, find the ordinate of the point on the line, whose abscissa is –1.
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Answer 1

The ordinate of the point which passes through (3,4) and (5,6) and with abscissa -1 is 0.

A straight line is drawn joining the points (3,4) adn (5,6).

We have to find the ordinate of the point whose abscissa is -1, we have to find the ordinate of the point.

To find the ordinate, we first find the equation of line passing through the points.

Equation of line in two point form is

$\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}$

where, (x_1,y_1) and (x_2,y_2) are the two points.

Now , Equation of line passing through (3,4) and (5,6) is

$\frac{y-4}{x-3} = \frac{6-4}{5-3}$

y - 4 = x - 3

x - y + 1 = 0

Now the point whose abscissa is -1 passes through this line, we have to find the ordinate.

-1 - y + 1 =0

y = 0.

The ordinate of the point whose abscissa is -1 is 0.