A straight line passes through the point (3,2) and the portion of this line, intercepted between the positive axes, is bisected at this point. Find the equation of the line.
SARDARshubham:
hey, can you explain the question briefly ?
I think we just hv to make a equation using the given coordinates
I m also a bit confused about it
ya, but there is a condition given .
wht
that's only confusing me !
me too
I am also confused about the question
It is saying about some interception
Answers
Answered by
94
Let the line intersect x-axis at (x,0) & y-axis at (0,y)
Given that this line is bisected by the point (3,2)
(3,2) = [(x+0)/2 , (0+y)/2]
3 = x/2
x = 6
2 = y/2
y = 4
---------------------------------
Hence the line intersects x-axis at (6,0) & y-axis at (0,4)
The equation of line of two point form is given by ;
(y-y₁) = {(y₂-y₁)/(x₂-x₁)} × (x-x₁)
(y-0) = [(4-0)/(0-6)] × (x-6)
y = (4/-6) × (x-6)
y = [(2/-3)×x] - [(2/-3)×(-6)]
y = (2x/-3) - (4)
y = (2x-12)/-3
-3y = 2x-12
2x+3y = 12
_________________________
Hence the required equation of line is
2x+3y = 12
Given that this line is bisected by the point (3,2)
(3,2) = [(x+0)/2 , (0+y)/2]
3 = x/2
x = 6
2 = y/2
y = 4
---------------------------------
Hence the line intersects x-axis at (6,0) & y-axis at (0,4)
The equation of line of two point form is given by ;
(y-y₁) = {(y₂-y₁)/(x₂-x₁)} × (x-x₁)
(y-0) = [(4-0)/(0-6)] × (x-6)
y = (4/-6) × (x-6)
y = [(2/-3)×x] - [(2/-3)×(-6)]
y = (2x/-3) - (4)
y = (2x-12)/-3
-3y = 2x-12
2x+3y = 12
_________________________
Hence the required equation of line is
2x+3y = 12
Sorry the answer is wrong
2x + 3y = 12 is the correct answer
ok
Now, it's right !
Sorry, earlier I was little confused.... but not is OK
Thanks :)
I'm glad, I was of any help to you :-)
It was a great help ^_^
Answered by
19
hope this answer would help u
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