Question

A straight line passing through the point (4, 5) has a slope of
3/5. What can be another point on the straight line? Why?

Answer 1

So the line is 

(y - 4) = 3/5(x - 5)
5y - 20 = 3x - 15
3x - 3y + 5 = 0
So the Equation of the line is 3x - 3y + 5 = 0
so the points satisfying this line will be the answer

so let us take x =  0 

then 3 x 0 - 3y = - 5
   y = 5/3

so the point passing the line is (0 , $\frac{5}{3}$)