A straight tree is broken by the wind. It's top touches the ground 100m away at an angle of 60 degree. find height of the broken part
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Answers
Questions:
A tree is broken by the wind. The top of that tree struck the ground at an angle of 30° and at a distance of 30m from the root. Find the height of the whole tree.
Answer:
Segment AB represents the height of the tree.
Segment AB represents the height of the tree.The tree breaks at point D.
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DC
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30m
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,tan30°=BD/BC
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,tan30°=BD/BC1/✓3=BD/30
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,tan30°=BD/BC1/✓3=BD/30BD=30/✓3
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,tan30°=BD/BC1/✓3=BD/30BD=30/✓3Also cos30°=BC/DC
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,tan30°=BD/BC1/✓3=BD/30BD=30/✓3Also cos30°=BC/DC✓3/2=30/DC
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,tan30°=BD/BC1/✓3=BD/30BD=30/✓3Also cos30°=BC/DC✓3/2=30/DCDC=60/✓3
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,tan30°=BD/BC1/✓3=BD/30BD=30/✓3Also cos30°=BC/DC✓3/2=30/DCDC=60/✓3DC=20✓3m
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,tan30°=BD/BC1/✓3=BD/30BD=30/✓3Also cos30°=BC/DC✓3/2=30/DCDC=60/✓3DC=20✓3mHence AD=DC=20✓3m
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,tan30°=BD/BC1/✓3=BD/30BD=30/✓3Also cos30°=BC/DC✓3/2=30/DCDC=60/✓3DC=20✓3mHence AD=DC=20✓3mFrom the figure, AB=AD+DB
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,tan30°=BD/BC1/✓3=BD/30BD=30/✓3Also cos30°=BC/DC✓3/2=30/DCDC=60/✓3DC=20✓3mHence AD=DC=20✓3mFrom the figure, AB=AD+DBAB=20✓3+10✓3
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,tan30°=BD/BC1/✓3=BD/30BD=30/✓3Also cos30°=BC/DC✓3/2=30/DCDC=60/✓3DC=20✓3mHence AD=DC=20✓3mFrom the figure, AB=AD+DBAB=20✓3+10✓3AB=30✓3m
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,tan30°=BD/BC1/✓3=BD/30BD=30/✓3Also cos30°=BC/DC✓3/2=30/DCDC=60/✓3DC=20✓3mHence AD=DC=20✓3mFrom the figure, AB=AD+DBAB=20✓3+10✓3AB=30✓3mAB=30×1.73
Segment AB represents the height of the tree.The tree breaks at point D.∴ Segment AD is the broken part of tree which then takes the position of DC.∴AD=DCGiven m∠DCB=30°,BC=30mIn right angled ΔDBC,tan30°=BD/BC1/✓3=BD/30BD=30/✓3Also cos30°=BC/DC✓3/2=30/DCDC=60/✓3DC=20✓3mHence AD=DC=20✓3mFrom the figure, AB=AD+DBAB=20✓3+10✓3AB=30✓3mAB=30×1.73AB=51.9m
Hence, the height of tree is 51.9m.
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Answer:
51.9m
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