Question

motorcycle racer takes a round with speed 20 m/s in a curvature of
radius R= 40m, then leaning angle of motor cycle for safe turn is ,(g=10 m/S2)

Answer 1

Answer:

⛔=45°

Explanation:

⛔ = tan°-1(v°2/Rg)

= tan°-1(20)°2 / 40×10

=tan°-1(400/400)

=tan°-1(1)

=45°

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