A straight wire carrying a current of 10amperes is placed in such a way that it's length runs in the north south and the current flow north.calculate the magnitude and illustrate the direction of the magnetic field produced by the current at a point 5cm east of the wire
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Answer:
A straight wire of length 2 m carries a current of 10 A . If this wire is placed in a uniform magnetic field of 0.15 T making an angle of 45^∘ ...
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Answer:
1.6×10
−17
N
B=
4π
μ
0
.
r
2i
=10
−7
×
0.1
2×10
=2×10
−5
wb/m
2
F=qvBsinθ
=(1.6×10
−19
)(5×10
6
)(2×10
−5
)sin90
0
=1.6×10
−17
Newton.
Explanation:
1.6×10
−17
N
B=
4π
μ
0
.
r
2i
=10
−7
×
0.1
2×10
=2×10
−5
wb/m
2
F=qvBsinθ
=(1.6×10
−19
)(5×10
6
)(2×10
−5
)sin90
0
=1.6×10
−17
Newton.
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