A straight wire of length 0.5 metre and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 tesla. If the magnetic field is perpendicular to the length of the wire , the force acting on the wire is
Answers
1.2N
Explanation:
Length of the wire = 0.5m (Given)
Current = 1.2 ampere (Given)
Induction = 2 Tesla (Given)
Let B be the uniform magnetic field, the current in the wire of length L be I, Thus, the force due to magnetic field is given by
F = IL x B
L = 0.5m
I = 1.2 A
B = 2T
Therefore,
|F|= 1.20×0.5 ×2 × sin90
|F|= 1.20×0.5 ×2 × sin π/2
= 1.2
Therefore, if the magnetic field is perpendicular to the length of the wire, then the force on the wire is 1.2N
Answer:
1.2N
Explanation:
Length of the wire = 0.5m (Given)
Current = 1.2 ampere (Given)
Induction = 2 Tesla (Given)
Let B be the uniform magnetic field, the current in the wire of length L be I, Thus, the force due to magnetic field is given by
F = IL x B
L = 0.5m
I = 1.2 A
B = 2T
Therefore,
|F|= 1.20×0.5 ×2 × sin90
|F|= 1.20×0.5 ×2 × sin π/2
= 1.2
Therefore, if the magnetic field is perpendicular to the length of the wire, then the force on the wire is 1.2N
Explanation: