Question

A straight wire of length L is bent into a
semi-circular loop. Use Biot-Savart's law
to deduce an expression for the magnetic
field at its centre due to the current I
passing through it.​

Answer 1

Explanation:

The straight wire of the length “L” is bent into the semi-circular loop. To find this expression for a magnetic field at it’s center due to the current “I” passing through it.

We will be using the “Biot Savart’s Law” to find a magnetic field.  

$B=\frac{\mu_{o} i}{4 \pi R^{2}} \int d l$

Where, I denotes the current, R is the radius of the wire, “l” is a length of the wire and is also constant of permeability.