Question

A straight wire of linear charge density a = 3 uC/mand area of cross section A = 4 mm² is given asshown in figure. When wire is pulled with speed 2m/s, then current associated with it is

Answer 1

Answer:

The current associated with it is $i = 6 \mu A$

Explanation:

As we know that rate of flow of charge is known as electric current

so we will have

$i = \frac{dq}{dt}$

here we know that

$dq = \lambda dx$

so we have

$i = \frac{dq}{dt}$

$i = \lambda \frac{dx}{dt}$

$i = \lambda v$

here we know that

$\lambda = 3\mu C/m$

$v = 2 m/s$

now we have

$i = 3\mu C/m \times 2 m/s$

$i = 6 \mu A$

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Answer 2

The current is 6μA.

Explanation:

Given that,

Linear charge density $\lambda=3\ \mu C/m$

Area of cross section A=4mm²

Speed = 2 m/s

We need to calculate the current

Using formula of current

We know that,

The rate of flow of charge is electric current

$i=\dfrac{dq}{dt}$

We know that,

$dq=\lambda dx$

$i=\dfrac{\lambda dx}{dt}$

$i=\lambda v$

Put the value into the formula

$i=3\ \muC\times 2$

$i=6\ \mu A$

Hence, The current is 6μA.

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Topic : current

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