Question

A straight wire of linear charge density lambda = 3 mu coloumb

Answer 1

aI think lemda=q/l .......

Answer 2

$i=6\mu A$

Explanation:

We know that,

The rate of flow of charge is known as electric current.

∴ $i=\dfrac{dq}{dt}$    ...... (1)

Also,

$dq=\lambda dx$     .........(2)

From equations (1) and (2), we get

$i=\dfrac{dq}{dt}$

⇒ $i=\lambda \dfrac{dq}{dt}$

⇒ $i=\lambda v$

Where, $\lambda$ is the wavelength, i is the current

Also, we know that

$\lambda=3\frac{\mu C}{m} \times 2m/s$

$i=6\mu A$

You can refer:

https://brainly.in/question/14324363