Question

A straw is place into a rectangle box that is 4 inches by 5 inches by 9 inches. If the straw fits into the box diagonally from the bottom left corner to the top right back corner, how long is the straw?

Answer 1

$\bold \red{solution \: by \: rkrashan}$

$\bold \red{d = \sqrt{ {l}^{2} + {b}^{2} + {h}^{2} }}$

$\bold \green{d = \sqrt{ {4}^{2} + {5}^{2} + {9}^{2} } }$

$\bold \green{ d = \sqrt{122} \: inch }$

$\huge\underline\red{Hope \: it \: helps \: } \\ \: \huge\underline\green{Thank \: U}$

Answer 2

Answer:

let length of rectangular box is L=4, width is W=5 and hight is H=9.

let the distance between bottom left conner and bottom right conner  be "d" and can be find as by using Pythagoras theorem

d^2=L^2+W^2

by putting values we get

d^2=(4^2)+(5^2).

d^2=16+25

d^ 2=36

taking under root on both sides we get

d=6.

Let the distance between bottom left conner and right upper conner be "D"

and can be find as using again Pythagoras theorem

D^2=d^2+H^2

by putting values we get

D^2=(6^2)+(9^2)

D^2=36+81

D^2=117

taking under root on both sides we get

D=(117)^(1/2).

So length of straw is   (117)^(1/2).

Step-by-step explanation: