Question

A street lane is to be paved with tiles of length 12 cm and breadth 10 cm. If the length
of the lane is 240 m and its breadth is 12 m, find the number of tiles needed.​

Answer 1

$area \: of \: lane = 240 \times 12 = 2880$

$area \: of \: tiles = 12 \times 10 = 120$

$number \: o f\: tiles \: needed = \frac{2880}{120} = 24$

Answer 2

Answer:

Number of Tiles = 2,40,000

Step-by-step explanation:

Dimensions of Tile = 12 × 10 cm²

Dimensions of Lane = 240 × 12 m²

$Number\ of\ Tiles =\frac{Dimensions of Lane}{Dimensions of Tile}$

⇒ $\frac{240*12m^{2} }{12 * 10cm^{2} } = \frac{24000*1200cm^{2} }{12 * 10cm^{2} } = 2,40,000$