a stretched string of mass 20 grams vibrates with a frequency of 30 Hertz in its fundamental mode and the supports are 40 cms apart. The amplitude of vibrations at the antidote is 5 Cms. calculate the velocity of propogation of the waves in the string as well as the tension on it answer this quesstion
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Wave Speed Formula:

Calculate the velocity of propagation of the wave in the string.
Let L be the length of string.

the tension:
We know,

Then,
So,

Calculate the velocity of propagation of the wave in the string.
Let L be the length of string.
the tension:
We know,
Then,
So,
Pavansm:
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