Question

A string breaks if its tension exceeds 10 newtons. a stone of mass 250 gm tied to this string of length 10 cm is rotated in horizontal circle. the maximum angular velocity of rotation can be

Answer 1

Answer: $\Rightarrow w=20rad/sec$

Given data states the T = 10 N at which string do not breaks to which a mass 250gm is tied to 10cm length string which rotated. So in order to maintain the tension the angular velocity maximum to support the given situation will be given by the equation,

                     $T=m\times w^{ 2 }\times l$

where w is the angular velocity.

                     $\Rightarrow w=\sqrt { \left[ \frac { T }{ m\times l } \right] }$

                     $\Rightarrow w=\sqrt { \left[ \frac { 10 }{ \left( \frac { 250 }{ 1000 } \times \frac { 10 }{ 100 } \right) } \right] }$

                     $\Rightarrow w=20rad/sec$

Answer 2

Answer:

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