Question

A string breaks under a tension of 10 kg-wt. If
the string is used to revolve a body of mass
12 g in a horizontal circle of radius 50 cm, what
is the frequency of revolution and linear speed
with which the body can be revolved?
(g = 9.8 m/s?]​

Answer 1

Explanation:

(a.) T

man

=10×g=100N

r=50cm=0.5m

m=1.2Kg

asT=

r

mv

2

as100=

0.5

1.2×v

2

⇒v=6.45

s

m

(b.) T=timeperiod

=

v

2πr

=

6.45

2π×0.5

=0.48s

(c.) f=frequencyofrevolution

=

Timeperiod

1

=

s

2.08