Question

A string free from one end is vibrating with
a frequency of 150 Hz. Which of the following
cannot be the possible frequency of vibration
of same string ?
(A) 50 Hz
(B) 250 Hz
(C) 300 Hz
(D) 450 Hz​

Answer 1

Answer:

Here is your answer

Option D

Hope it will helps you .:--)

Answer 2

Answer:

For a string free from one end , the frequency not possible will be (C) 300Hz

Explanation:

• For a string opened at one end the harmonics produced will be of nth order of natural frequency.
• fₙ = nf₁  where, fₙ is the nth harmonics ; f₁ is the natural frequency  and n is the odd integer.
• natural frequency is given by v/4L, where v is velocity and L is the length of the string.
• Thus the harmonics of a single open end will always be the odd integral value of natural frequency.

1. (A) 50 = n(150) ⇒ n = 1/3
2. (B) 250 = n·150 ⇒ n = 5/3
3. (C) 300 = n·150 ⇒ n = 2
4. (D) 450 = n·150 ⇒ n = 3

Thus, only 300 Hz was the even integral of 150 Hz. Therefore it cannot possibly be the frequency of same string.

#SPJ2