Question

A string free from one end is vibrating with
a frequency of 150 Hz. Which of the following
cannot be the possible frequency of vibration
of same string?
(A) 50 Hz
(B) 250 Hz
(C) 300 Hz
(D) 450 Hz​

Answer 1

Explanation:

s_7

55

using s=u+at

sh

ans 300

Answer 2

Answer:

The correct option is C) 300 Hz.

Explanation:

• The harmonics generated for a string that is opened at one end will be of the order n of natural frequency.
• When fn = nf1, n is the odd integer, f1 is the natural frequency, and fn is the nth harmonic.
• Natural frequency is equal to v/4L, where v represents speed and L is the string length.
• The odd integral value of natural frequency will thus always equal the harmonics of a single open end.
• 50/ 150 = 1/3
• 250 / 150 = 5/3
• 300 / 150 = 2
• 450 / 150 = 3
• 300 Hz is an even integral of 150 Hz

300 Hz cannot be the possible frequency.

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