Question

A string has a linear density of 8.5 x 10-3 kg/m and is under a tension of 280 N. The string is 1.8 m long, is
fixed at both ends, and is vibrating in the standing wave pattern shown in the drawing. Determine the
(a) speed,
(b) wavelength, and
(c) frequency of the traveling waves that make up the standing wave.

Answer 1

m = Linear mass density = 8.5 * 10^-3

T = Tension = 280N

v = Velocity of wave = $\sqrt{\frac{T}{m} }$

v = √(280/8.5 * 10^-3)

v = √32941.176 = 181.5 m/s

To find the frequency and wavelength we need to know the figure but the figure is not given here

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Answer 2

Answer:

You can obtain the V or speed by using the equation

1)V=square root of F/ (M/L)

M/L = linear density by the way

with that equation, V will be 181 m/s

Here's the setup Square root of 280/8.5 x10^-3= 181 m/s

2)Wavelength = 2L/3

L= 1.8

so take 1.8 x 2/3=1.2 m, so wavelength =1.2 m

3) frequency= v/lambda (wavelength)

so 181 m/s/1.2=150 hz.

Great job guys!

Explanation: