A string is used to pull up a block of mass m vertically up by a distance h at a constant acceleration g/3 . The work done by the tension in the string is
Answers
kx =4mg/3
Given: Mass of block = m
distance displaced = h
angle between force and displacement = 0°
acceleration = g/3
To find: the work done by the tension in the string
Solution: We know that, for work done:
W = F.s cos ∅
In the question, it is evident that force is the tension in the string. Also, s is the h distance displaced. Putting the given values in the formula, we get:
W = T. h. cos 0° __________(1)
Now, through the concept of pseudo force, we know that for acceleration and displacement of the body in the same direction, we have:
T = m ( g + a )
Putting the given values, we obtain:
T = m ( g + g/3)
T = 4mg / 3 _________(2)
Putting (2) in (1), we obtain:
W = 4mg/3 × h
W = 4mgh/ 3.
Hence, the work done by the tension in the string is 4mgh/3.