A string tied on a roof can bear a maximum tension of 50 kg wt the minimum acceleration that can be acquired by a man of 98 kg to descend will be take g=9.8 m/s
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FBD of man,
mg - T = ma
98x9.8 - 50 = 98a
960.4 - 50 = 98a
910.4 = 98a
a = 910.4/98
a = 9.2m/s²
mg - T = ma
98x9.8 - 50 = 98a
960.4 - 50 = 98a
910.4 = 98a
a = 910.4/98
a = 9.2m/s²
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according to question
mg-t=ma
98*9.8-50=98*a
a=9.3
mg-t=ma
98*9.8-50=98*a
a=9.3
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