a student collected apparrus for carrying out the experiment of finding equivalent resistane of a parallel combination of resistance. he observed that the ammeter given to him had 50 divisions and it could read upto 100mA . the least count of the ammeter will be:
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1mA=0.001A
So 100mA=0.1A
Least count=0.1/50
=0.002A
The least count is 0.002 A
So 100mA=0.1A
Least count=0.1/50
=0.002A
The least count is 0.002 A
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