Question

a student conducts an activity with a flask of height 12 cm and a concave mirror. he finds that the image formed is 48 cm in height. what are the possible magnifications of the image?​

Answer 1

Answer:

Correct option is

A

−10 cm

Given,

object height h

1

=1.5 cm

real image length h

2

=−3cm

Position of object from the mirror u=−15cm

Mirror magnification formula

m=

h

1

h

2

=−

u

v

1.5

−3

=

−15

−v

v=−30cm

Apply Mirror formula

f

1

=

−30

1

+

−15

1

f=−10cm

Explanation:

I hope this will help you.

Answer 2

Answer:

At 30cm on same side of the mirror.