Question

A student got twice as many sums wrong
as he got right. If he attempted 54 sums
in all, the number of sums he did correctly
is :​

Answer 1

Step-by-step explanation:

Let the number of sums he got right be 'x'

Number of sums he got wrong 2x

Total number of sums he attempted 2x+x=3x

3x=54

x=18

Therefore he got 18 sums correct.

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Answer 2

Answer:

20 sums

Step-by-step explanation:

Let the number of sums he got right be 'x',

Wrong sums be '2x'

Total number of sums = 60

∴2x + x = 60

3x=60

x=20

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