A student has to secure 40% marks to pass. He gets 178 marks and fails by 22 marks. The maximum marks are
Answers
Answered by
72
Answer:
500 marks
Step-by-step explanation:
Given
: a student has to secure 40 % marks to pass
: he gets 178 marks and fails by 22 marks
Then,
Pass marks = 178+22
Pass marks = 200
40% = 200 marks
200 marks = 40% of maximum marks
Maximum marks = pass marks × 100/40
Maximim marks = 200 × 100/40
Maximum marks =500 marks
The maximum marks in the exam are 500.
mukheer1977:
*Passing marks = 22
Answered by
54
Given,
Maximum percentage required to pass = 40 %
Marks the student got = 178 and fails by 22 marks.
Which means 178 + 22 will be the 40 %
So, the 40 % of the marks were,
178 + 22 = 200
If 40 % of the marks is 200, then the 100 % will be,
Setting up an equation,
Solving it,
20000 = 40x [Doing cross multiplication]
500 = x
Hence, the maximum marks were,
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