Question

A student has to secure 40% marks to pass. He gets 178 marks and fails by 22 marks. The maximum marks are

Answer 1

Answer:

500 marks

Step-by-step explanation:

Given

: a student has to secure 40 % marks to pass

: he gets 178 marks and fails by 22 marks

Then,

Pass marks = 178+22

Pass marks = 200

40% = 200 marks

200 marks = 40% of maximum marks

Maximum marks = pass marks × 100/40

Maximim marks = 200 × 100/40

Maximum marks =500 marks

The maximum marks in the exam are 500.

Answer 2

$\sf\underline{Step-by-step \: explanation}$

Given,

Maximum percentage required to pass = 40 %

Marks the student got = 178 and fails by 22 marks.

Which means 178 + 22 will be the 40 %

So, the 40 % of the marks were,

178 + 22 = 200

If 40 % of the marks is 200, then the 100 % will be,

Setting up an equation,

$\frac{40}{100} \: \times \: x \: = \: 200$

Solving it,

$\frac{40}{100} x \: = \: 200$

20000 = 40x [Doing cross multiplication]

500 = x

Hence, the maximum marks were,

$\huge\underline{500}$