Question

Calculate the electric potential at the surface of a gold nucleus. Given, the radius of the nucleus = 6.6 × 10⁻¹⁵ m and atomic number of gold = 79.

Answer 1

Potential (V) = K(Ze)/R

V= 9*10^9*79*1.6*10^-19/6.6*10^-15

From this you can calculate

Answer 2

Answer:

The electric potential at the surface of a gold nucleus is  $1.72\times10^{7}\ V$.

Explanation:

Given that,

Atomic number of gold = 79

Radius of the nucleus $r = 6.6\times10^{-15}\ m$

The electric potential is defined as:

$V =\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{Q}{r}$

Here, Q = charge

r = radius of nucleus

There are 79 protons inside the nucleus.

So,  the total charge will be $Q=79\times1.6\times10^{-19}$.

The potential at the surface of a gold nucleus

$V= \dfrac{9\times10^{9}\times79\times1.6\times10^{-19}}{6.6\times10^{-15}}$

$V = 1.72\times10^{7}\ V$

Hence, The electric potential at the surface of a gold nucleus is  $1.72\times10^{7}\ V$.