Question

A student has to secure 40% marks to pass he gets 90 marks and fails by 10 marks maximum marks are

Answer 1

★Minimum marks to pass the exam

= 90 + 10 = 100

★100 marks is 40% of Maximum marks

100 = 40% × Maximum marks

★Maximum marks

$\tt{\rightarrow 100\times\dfrac{100}{40}}$

= 250

★Maximum marks is 250.

Answer 2

Answer:

→ Maximum marks is 250.

Solution:

→ Minimum marks to pass the exam

= 90 + 10 = 100

→ 100 marks is 40% of Maximum marks

100 = 40% × Maximum marks

→ Maximum marks

→ $\tt{100\times\dfrac{100}{40}}$

→ Maximum marks is 250.