A student has to secure 50% marks to pass. He gets 163marks and fails by 37 marks. Find the maximum marks?
a. 500
b. 400
c. 1200
balsha:
400 marks
Answers
Answered by
38
Solutions :-
Given :
A student has to secure 50% marks to pass.
He gets 163 marks and fails by 37 marks.
Total pass marks = (163 + 37) = 200
Let the maximum marks be x
A/q
=> 50% of x = 200
=> 0.50 × x = 200
=> 0.50x = 200
=> x = 200/0.50 = 400
Hence,
The maximum marks = 400
Given :
A student has to secure 50% marks to pass.
He gets 163 marks and fails by 37 marks.
Total pass marks = (163 + 37) = 200
Let the maximum marks be x
A/q
=> 50% of x = 200
=> 0.50 × x = 200
=> 0.50x = 200
=> x = 200/0.50 = 400
Hence,
The maximum marks = 400
thanks :)
Answered by
38
Solutions :-
Let the maximum marks be x
We have,
Percentage of marks to pass = 50% of total = 0.50 × x
He gets 163 marks and fails by 37 marks.
Total pass marks to pass exam = (163 + 37) = 200
Find the value of x :-
A/q
=> 0.50 × x = 200
=> 0.50x = 200
=> x = 200/0.50 = 400
Answer : Maximum marks to pass the exam = 400
Let the maximum marks be x
We have,
Percentage of marks to pass = 50% of total = 0.50 × x
He gets 163 marks and fails by 37 marks.
Total pass marks to pass exam = (163 + 37) = 200
Find the value of x :-
A/q
=> 0.50 × x = 200
=> 0.50x = 200
=> x = 200/0.50 = 400
Answer : Maximum marks to pass the exam = 400
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