A student has two resistor 2 columb and 3 columb she has to put one of them in place of R2 as shown in circuit .The current that she needs in the entire circuit is exactly 9A shown by calculation which of the two resistor she should choose
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The overall current needed = 9A. The voltage is 12V Hence by Ohm’s Law V=IR, The resistance for the entire circuit = \(\frac{12}{9}\) = \(\frac{4}{3}\Omega\) = R R1 and R2 are in parallel. Hence, R=\(\frac{(R_1R_2)}{(R_1+R_2)}\)= \(\frac{4R_2}{(4+R_2)}\)= \(\frac{4}{3}\) R2 = 2\(\Omega\)Read more on Sarthaks.com - https://www.sarthaks.com/972176/student-has-two-resistors-and-she-has-to-put-one-of-them-in-place-of-r2-as-shown-in-the-circuit?show=972187#a972187
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