Chemistry, asked by dylang10024, 1 year ago

A student is given the question: "what is the mass of a gold bar that is 7.379 × 10–4 m3 in volume? the density of gold is 19.3 g/cm3."

The student obtains the answer through the following calculation:

answer=7.379×10^−4 m3×(100 cm/1 m​)^3. ×. 19.3 g?cm^3

What is the answer to the equation? Write your answer to the correct number of significant figures.

Answers

Answered by kobenhavn
2

Answer: The mass of gold bar is  1.42\times 10^4g

Explanation:

To calculate mass of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

We are given:

Density of gold bar = 19.3g/cm^3

Volume of gold bar = 7.379\times 10^{-4}m^3=737.9cm^3  

(Conversion factor: 1m^3=10^6cm^3  )

Putting values in above equation, we get:

19.3g/cm^3=\frac{\text{Mass of gold bar}}{737.9cm^3}\\\\\text{Mass of gold bar}=1.42\times 10^4g

Hence, the mass of gold bar is 1.42\times 10^4g

Answered by amramujeeb7862003
0

Answer: the answer is 1.42x10^4g

Explanation: b\7.379 × 10–4 m3 in volume? the density of gold is 19.3 g/cm3."

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