Question

A student is given the question: "what is the mass of a gold bar that is 7.379 × 10–4 m3 in volume? the density of gold is 19.3 g/cm3."

Answer 1

vol. =7.379 × 10–4 m3 =7.379 × 10^–4×10^6 cm3

=7.379×10^2 cm3

density =19.3 g/cm3.

mass = vol.×density = 7.379×10^2*19.3

=14241.47 g

=14.24147 kg

Answer 2

Answer : The mass of a gold bar is, 14241.47 g

Solution : Given,

Density of a gold bar = $19.3g/cm^3$

Volume of a gold bar = $7.379\times 10^{-4}m^3=7.397\times 10^{2}cm^3$

$(1m^3=10^6cm^3)$

Formula used :

$\text{Mass of a gold bar}=\text{Density of gold bar}\times \text{Volume of gold bar}$

Now put all the given values in this formula, we get

$\text{Mass of a gold bar}=(19.3g/cm^3)\times (7.379\times 10^{2}cm^3)=14241.47g$

Therefore, the mass of a gold bar is, 14241.47 g