Question

a student is standing at a distance of 50 m behind a bus. as soon as the bus begins its motion with acceleration of 1m/s the student starts running towards the bus with a uniform velocity u. assuming the motion to be along a straight line , the minimum value of u so that the student is able to catch the bus in 10 sec is

Answer 1

Answer:

u min = 10 m/s

Explanation:

Acceleration of bus a = 1 m/s

In 10 seconds, the distance travelled by te bus S can be given as

S = ut + 1/2 at²

as initial velocity of bus is zero,

S = 0 + 0.5×1×10²

∴S = 50 m ....(1)

Student in behind the bus by 50 m

As calculated above, bus travels distance = 50 m.

Thus, the students must travel min distance = 50 + 50 = 100 m

Uniform velocity of student can be calculated as

U = Distance traveleed ÷ time taken

∴ U = 100 ÷ 10

∴ U = 10 m/s

Minimum value of u, (uniform velocity by the student) so that the student is able to catch the bus = 10 m/s

Answer 2

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