Question

A student measured the length of a box to be 75cm, but the box was actually 60cm long. what was the percent error in this measurement?

Answer 1

Answer:

i dont know the answer for this question

Step-by-step explanation:

Answer 2

Answer:

Percentage error is 25%

Step-by-step explanation:

Actual length $l_{o}=60 cm$

Measured length $l_{f}=75 cm$

Percentage error is

$=\frac{l_{f}-l_{o}}{l_{o}} \times 100\\=\frac{75-60}{60} \times 100\\=25 %$

Percentage error is 25%