Question

a student measures the time period of 100 oscillations of a simple pendulum four times.that data set is 90s,91s,95s,and 92s. if the minimum division in the measuring clock is 1s, then the reported mean time should be

Answer 1

Data set ={90,91,95,92}

mean = (90+91+95+92)/4 = 368/4 = 92s

Since the least count is 1s, we can measure 92s.

So reported mean time should be 92s.

If the mean had come out to be 90.3s or 90.4s, you should have reported it as 90s as least count is 1s and you can not measure 0.3 or 0.4 s

Answer 2

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Data set ={90,91,95,92}

mean = (90+91+95+92)/4 = 368/4 = 92s

Since the least count is 1s, we can measure 92s.

So reported mean time should be 92s.

If the mean had come out to be 90.3s or 90.4s, you should have reported it as 90s as least count is 1s and you can not measure 0.3 or 0.4 s

HOPE SO IT WILL HELP......