Question

ABC is an isosceles triangle in which AB=AC. By drawing AP perpendicular BC show that ANGLE B = angle C

Answer 1

Answer:

Step-by-step explanation:

Given: in ΔABC, AB = AC

To prove: ∠B = ∠C

Proof: Consider Δ’s ADB and ADC

AB = AC (Given)

∠ADB = ∠ADC = 90° [Since AD ⊥ BC]

AD = AD [Common side]

⇒ ΔADB ≅ ΔADC [By RHS congruence rule]

∴ ∠B = ∠C  [CPCT]

Answer 2

Hello mate ^_^

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Solution:

In △ABP and △ACP

AB=AC        (Given)

∠APB=∠APC          (Each equal to 90°)

AP=AP        (Common)

Therefore, by RHS congruence rule, △ABP≅△ACP

Hence, ∠B=∠C            (Corresponding parts of congruent triangles are equal)

hope, this will help you.

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