a student multiples the month and day in which he was born by 31 and 12 respectively. the sum of two resulting products is 170. what was the month and the date which he was born?
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Answered by
1
Answer:
(x*31)+(y*12)=170.
31x+12y=170.
x=170/31.
5.48.
y=170/12.
14.16.
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Answered by
1
Answer:
Let the month be = x
Let the day be = y
According to the question:
31x + 12y = 170
=> x = (170 - 12y)/31
Maximum value of x = 12 [Since there are only 12 months]
Maximum value of y = 31 [Since there can be maximum only 31 days in a month]
Since neither of the month and the day can be in fraction, we need to find the value of y which satisfies the above equation and is in a whole number.
Now, by trial and error method, we find that the value of y as 9, brings us to a whole number.
x = (170 - 12(9))/31
=> x = 62/31
=> x = 2
Thus, month is 2 (February) and day is 9.
Date of birth = 9th February
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