A student of mass 75kg climbs stairs with a total height of 8.0m. The gravitational field strength is 10N/kg.
(a) Calculate the weight of the student.
(b) Calculate the gain in gravitational potential energy of the student when he climbs the stairs.
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gravitational field strength is bacially avceleration due to gravity...
E =F/M
so weight of student = m×g
=75×10
750...
gain in p.E= mgh
750 × 10 ×8 =60000 joule
E =F/M
so weight of student = m×g
=75×10
750...
gain in p.E= mgh
750 × 10 ×8 =60000 joule
Answered by
0
(a)=gravitational field strength
E =F/M
∴ weight of student = m×g
⇒75×10
⇒750
(b)gain in P.E= mgh
⇒750 × 10 ×8
⇒60000 joule
E =F/M
∴ weight of student = m×g
⇒75×10
⇒750
(b)gain in P.E= mgh
⇒750 × 10 ×8
⇒60000 joule
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