Question

A student pushes down with a force of 2N on the plunger of syringe A. Syringe B has a plunger with an area that is 3 times the area of plunger A. What is the force produced by plunger B? Pls answer this question

Answer 1

Answer:

The force produced by plunger B is 6 Newtons (N).

Explanation:

For this problem, we need to use a bit of algebra.

Let us assume the area of plunger A as $x$.

Force produced by plunger A is 2 N.

Pressure = $\frac{Force}{Area}$

Pressure = $\frac{2N}{x}$

As the question mentions the area of plunger B is 3 times plunger A's area, it will be 3x according to the statement above.

Force = Pressure * Area

Force = $\frac{2N}{x}$ * $3x$

The $x$ variable gets cancelled out.

So, the only numbers remaining are:

2 * 3 = 6 Newtons.

Therefore, the force produced by plunger B is 6 Newtons (N).