CBSE BOARD X, asked by sidaabhadamaaisalo, 1 year ago

A student takes a mixture of sand and ammonium chloride in china dish and heats it under a funnel fitted with a plug over a flame. He would observe that: (1) solid sand gets deposited on the lower cooler parts of the funnel while solid ammonium chloride remains in the china dish. (2) sand and ammonium chloride get deposited on hotter parts of the funnel. (3) ammonium chloride gets deposited on the cooler parts of the funnel and sand remains in the china dish. (4) sand collects on cooler parts of the funnel while ammonium chloride melts in the china dish.

Answers

Answered by rishilaugh
36
 Answer: (3) Sand is a non-sublimable solid and ammonium chloride is a sublimable solid. Being a sublimable solid, ammonium chloride changes directly from the solid to the gaseous state on heating, and gets deposited on the cooler parts of the funnel. On the other hand, sand remains in the china dish.
Answered by srose
1

Answer:

(3) Sand is a non-sublimable solid and ammonium chloride is a sublimable solid. Being a sublimable solid, ammonium chloride changes directly from the solid to the gaseous state on heating, and gets deposited on the cooler parts of the funnel. On the other hand, sand remains in the china dish.

Explanation:-

When a mixture of common salt and ammonium chloride is heated, it is observed that Ammonium chloride gets deposited on the cooler parts of the funnel and solid common salt remains in the china dish because  

Ammonium chloride, anthracene, napthalene can sublime but common salt cannot sublime. Ammonium chloride evaportaes and forms vapours which rise up the funnel and get deposited in the cooler parts of the funnel. Sodium chloride remains in the china dish as no reaction takes place.

Sublimation is the transition of a substance directly from the solid to the gas phase without passing through the intermediate liquid phase.

Hence option 3 is correct

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