A student uses a lens of focal length 40 cm and another of -20 cm write the nature and power of each lens
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Hey buddy.....here's your answer
Focal length of lens 1=40cm
The lens is convex lens.So,the nature of the image is real and inverted.
Power 1=P1=1/f1=1/40=0.025D
Focal length of lens 2= -20cm
The lens is concave lens.So,the nature of the image is virtual and erect.
Power 2=P2=1/f2=1/-20= -0.05D
I hope this will be helpful
Focal length of lens 1=40cm
The lens is convex lens.So,the nature of the image is real and inverted.
Power 1=P1=1/f1=1/40=0.025D
Focal length of lens 2= -20cm
The lens is concave lens.So,the nature of the image is virtual and erect.
Power 2=P2=1/f2=1/-20= -0.05D
I hope this will be helpful
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