A student was asked to multiply a number by 5/3. He multiplied by 3/5 instead. Find the percentage error in the calculation.
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The percentage error in the calculation is 64%.
Step-by-step explanation:
Since we have given that
A student was asked to multiply a number by 5/3.he multiple it by 3/5 instead.
Let the number be 'x'.
According to question, we get that
\begin{gathered}\dfrac{5}{3}x-\dfrac{3}{5}x\\\\=\dfrac{25x-9x}{15}\\\\=\dfrac{16x}{15}\end{gathered}35x−53x=1525x−9x=1516x
So, the percentage error would be
\begin{gathered}\dfrac{16x\times 3}{15\times 5x}\times 100\\\\=\dfrac{16}{25}\times 100\\\\=16\times 4\\\\=64\%\end{gathered}15×5x16x×3×100=2516×100=16×4=64%
Hence, the percentage error in the calculation is 64%.
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