Question

A student with a normal eye observes the reading on a vernier scale using a magnifying glass of
focal length 10 cm. What are the minimum and the maximum distances between the scale and the
magnifying glass at which he can read the scale when viewing through the magnifying glass?​

Answer 1

Answer:

Solution :

(i) What is the least distance of distinct vision of human eye? <br> What is the minimum distance between an object and a convex lens to obtain the virtual image? <br>

substitute f = 10 cm and v =

to obtain 'u'. <br> (ii)

cm <br>

= 10 cm

Answer 2

Answer:

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Explanation:

Using the magnifying glass object could be seen at least distance of distance vision at 25 cm.

1f=1v−1u110=1v−1251v=750v=7.14 cm1f=1v-1u110=1v-1251v=750v=7.14 cmm.

Minimum distance

Maximum distance e object will be at infinite distance.

1f=1v−1u110=1v−1∞v=10 cm