A students walks from his house to school at 8km/hr,he is late by 10 mintuss.however ,if he walks 10 km/hr,he is before by 5 mintuss .find its usual time to cover journey?
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Answer:
12.5 km
Explanation:
If the required distance be x km, then
x5−x6=30−560
=> 6x−5x30=2560=512
=> x = 30×512
= 12.5 km
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