Question

A submarine after traveling 100 km from the shore descended 1 1/10 below the sea level.Then it ascended about 3/5 km.The next day,it again descended by 9/10 km.what is its current position with respect to the sea ? what the horizontal distance of the submarine from the sea shore?

Answer 1

1*1/10 = (10 * 1 + 1)/10  = (10 +1)/10 = 11/10
∴  - (11/10) + (6/10) - (9/10)    [as 3/5 = 6/10]
⇒ - (14/10)
∴ the current position with respect to sea is 14/10 km .