A submarine after traveling 100 km from the shore, descended by 1 1/10 km below the sea level . Then it ascended about 3/5 km. The next day, it again descended by 9/10 km. What is it's current position with respect to the sea level ? What is the horizontal distance of the submarine from the sea shore ?
Answers
Answer:
The current position is 1/2 km below sea level. Horizontal distance of the submarine from the sea shore is 100 km.
Step-by-step explanation:
Submarine's position = 0
After descending,
Submarine's position = -11/10 km
Distance ascended = 3/5 km
Hence, submarine's current position = (-11/10 + 3/5) km = -5/10 km = -1/2 km
Answer:
★ 98.6 or 99 km ★
Step-by-step explanation:
Given:
- Submarine after travelling 100 km from the sea shore descended by 11/10 km
- After that it ascended by 3/5 km
- At last next day it again descended by 9/10 km
To Find:
- Current position of submarine and horizontal distance of it from sea shore.
Solution: Actual distance of submarine is 100 km
• In first case Submarine descended by 11/10 km •
→ 100 – 11/10
→ 1000–11/10 ( Take LCM )
→ 989/10
→ 98.9 km ( Current position of Submarine after descending 11/10km)
• Now in second case submarine ascended by 3/5 km •
→ 98.9 + 3/5
→989/10 + 3/5 ( Take LCM )
→ 989+6/10
→ 995/10
→ 99.5 km ( Current position of Submarine after ascending 3/5 km)
• In third case , Submarine again descended by 9/10 km •
→ 99.5 – 9/10
→ 995/10 – 9/10 ( Take LCM )
→ 995–9/10
→ 986/10
→ 98.6 km ( Current and final position of Submarine after descending by 9/10 km)
Hence, Submarine is at 98.6 or 99 km from the sea shore.