Question

A Submarine after travelling 100 km from the shore, descended
1 1/10 km below the sea level. Then it ascended about 3/5 km. The next day, it again descended by 9/10 km. What is it's current position with respect to the sea level? What is the horizontal distance of the submarine from the sea shore?

Answer 1

the current position with respect to the sea level is
-11/10+3/5-9/10= -14/10 km= -1.4 km
the horizontal distance is 100 km.

Answer 2

Answer:

Horizontal displacement = 100 km

Position with respect to sea level = -1.4km

Step-by-step explanation:

Lets take the displacement downwards to be negative displacement and displacement upwards to be positive.

The horizontal distance from the shore remains constant whereas the displacement from the sea level varies as the submarine moves.

The upward displacement = 3/5 km

Downward displacement = - 11/10 km and - 9/10 km

Total displacement = 3/5km - 11/10 km - 9/10km = - 7/5 km = - 1.4 km

Horizontal distance from the shore = 100km