a submarine after travelling 100 km from the shore, descended, 1/10 km below the sea level, then it ascended about 3/5 km. The next day, it again descended by 9 /10 km. what is its current position with respect to the sea level? What is the horizontal distance of the submarine from the sea level?
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Answer:
Position of Submarine = -1 ^ 1/10 + 3/5 - 9/
10
= - 11/10 + 3/5 - 9/10
= - 11 + 6 - 9
10
= - 11 - 9 + 6
10
= - 20 + 6
10
-14/10
= - 7/5
= - 1 ^2/5
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